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OpenStudy (anonymous):
What is the probability that a randomly chosen point lies in the shaded region? (leave the answer as a fraction and leave pi in your answer)
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OpenStudy (anonymous):
area of shaded region divided by total area
OpenStudy (anonymous):
|dw:1335835348734:dw|
OpenStudy (anonymous):
the triangle is shaded
OpenStudy (anonymous):
ok so the area of the circle is easy enough right? since the radius is 5 the area is \(\pi\times 5^2=25\pi\)
OpenStudy (anonymous):
Yes, I have that so far.
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OpenStudy (anonymous):
and you have two triangles both with base 5 and height 5 so the total area of the two triangles is
\(5\times 5=25\)
OpenStudy (anonymous):
take the ratio to get your answer
OpenStudy (anonymous):
So then isn't it just one..
OpenStudy (anonymous):
oh no the areas are not the same
OpenStudy (anonymous):
your shaded region has area 25, total circle has area \(25\pi\)
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OpenStudy (anonymous):
oh wait never mind... so it's 25pi over 25?
OpenStudy (anonymous):
no other way around
shaded area over total area
OpenStudy (anonymous):
so 25 over 25pi?
OpenStudy (anonymous):
don't forget probability is a number between 0 and 1
right
cancel the 25
OpenStudy (anonymous):
1pi? hahha
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OpenStudy (anonymous):
\(\frac{25}{25\pi}=\frac{1}{\pi}\)
OpenStudy (anonymous):
not \(1\pi\) but rather \(\frac{1}{\pi}\)
OpenStudy (anonymous):
Okay thank you!
OpenStudy (anonymous):
yw
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