What is the probability that a randomly chosen point lies in the shaded region? (leave the answer as a fraction and leave pi in your answer)
area of shaded region divided by total area
|dw:1335835348734:dw|
the triangle is shaded
ok so the area of the circle is easy enough right? since the radius is 5 the area is \(\pi\times 5^2=25\pi\)
Yes, I have that so far.
and you have two triangles both with base 5 and height 5 so the total area of the two triangles is \(5\times 5=25\)
take the ratio to get your answer
So then isn't it just one..
oh no the areas are not the same
your shaded region has area 25, total circle has area \(25\pi\)
oh wait never mind... so it's 25pi over 25?
no other way around shaded area over total area
so 25 over 25pi?
don't forget probability is a number between 0 and 1 right cancel the 25
1pi? hahha
\(\frac{25}{25\pi}=\frac{1}{\pi}\)
not \(1\pi\) but rather \(\frac{1}{\pi}\)
Okay thank you!
yw
Join our real-time social learning platform and learn together with your friends!