Question

square root 8x - 20 - square root 12
answers: x = –1, x = 15, x = 4, or None of the above

Answer 1

Do you mean\[\sqrt{8x-20}=\sqrt{12}\]

Answer 2

yes

Answer 3

\[\sqrt{8x-20}=\sqrt{(2\times2\times2)x-(2\times2\times5)}=2\sqrt{2x-5}\]
\[\sqrt{12}=\sqrt{2\times2\times3}=2\sqrt{3}\]

Answer 4

so which one of the answers i put above is it?

Answer 5

4?

Answer 6

\[\sqrt{8x-20}=\sqrt{12}\]
can be simplified to
\[2\sqrt{2x-5}=2\sqrt{3}\]

Answer 7

Can you simplify it further?

Answer 8

so...which one is it?
no i cant :(

Answer 9

subtract 2 from both sides and then square each side and solve for x

Answer 10

can you show me?

Answer 11

if you subtract 2 from both sides you get\[\sqrt{2x-5}=\sqrt{3}\]

Answer 12

so then it would be -1, or none of the above?

Answer 13

square each side to get\[2x-5 = 3\] and solve for x to get

Answer 14

\[x=\left( 5+3 \over 2 \right)\]

Answer 15

6.2?

Answer 16

\[x=\left( 3+5\over2 \right)=\left( 8 \over 2 \right)=4\]

Answer 17

can you help me with another?

Answer 18

sure

Answer 19

Solve.

Answer 20

thats a 7 btw

Answer 21

\[-5\sqrt{x-9}-7 = 23\]
Is this correct?

Answer 22

yes

Answer 23

ok
\[-5\sqrt{x-9}=30\]
divide each side by -5\[\sqrt{x-9}=-6\]

Answer 24

can you solve for x from here?