Question

the side of a cube is expanding at a constant rate of 6 inches per second. What is the rate of change of the volume, in inches^3 per second, when the total surface area of the cube is 54 inches^2?? Help.!

Answer 1

ds/dt = 6 in/sec
S.A = 6s^2
54 = 6 s^2
54/6 = s^2
9 = s^2
s = 3
volume = s^3
dv/dt = 3s^2 ds/dt
dv/dt = 3*3^2*6
dv/dt = 162

Answer 2

what does the s stand for in ds/dt. i know that the t stands for time

Answer 3

change in side with respect to time
let s = side

Answer 4

oh okay i got you now.

Answer 5

can you verify the answer ?