Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

The sum of three consecutive terms of a geometric sequence is 73.5. If the product of these terms is 2744, what are the terms?

OpenStudy (anonymous):

56 , 14 and 3.5 56+14+3.5=73.5 56*14*3.5=2744

OpenStudy (anonymous):

How did you get that?

OpenStudy (anonymous):

this question was asked during one of my mathematical examinations..i still remember it as a matter of fact

OpenStudy (anonymous):

WOAH. That is awesome. SO how did you solve for it when you were taking the exam?

OpenStudy (anonymous):

Let x be the first element and r be the common ratio x + r x + r^2 x = 73.5 x (rx)(r^2x)= 2744 You solve the two equations for x and r and you find two real solutions x=3.5 and r =4 or x=56 and r =1/4 Both yield the same 4 numbers.

OpenStudy (anonymous):

how is it r^2?

OpenStudy (anonymous):

let us suppose the three terms are \[{{a}\over{r}}, {a}, {ar}\] then \[{{a}\over{r}}+{a}+{ar} = 73.5\] and \[{{a}\over{r}}\times{a}\times{ar}=2744\] \[{a^3}=2744\] \[{a}=14\] now plug in this value in first equation \[{a}({{1}\over{r}}+{1}+{r}) = 73.5\] \[{14}({{1+r+r^2}\over{r}}) = 73.5\] \[{14}({{1+r+r^2}}) = 73.5r\] \[{14 +14r + 14r^2} = 73.5r\] \[{14r^2 -59.5r + 14} = 0\] now solve for r

OpenStudy (anonymous):

.0O0. I bow down to your awesomeness! Thank you!!!!!

OpenStudy (anonymous):

still having any difficulty ?

OpenStudy (anonymous):

well, why do you assume that they are a/r, a, and ar?

OpenStudy (anonymous):

because they are three consecutive numbers of the GP each having a common ratio in this case Common ration is r

OpenStudy (anonymous):

and i was having multiplication so r gets cancelled and easy for calculation

OpenStudy (anonymous):

GP?

OpenStudy (anonymous):

Geometric Sequence or, Geometric Progression or, Geometric Series

OpenStudy (anonymous):

oh! so like that other person was saying about the a+ar+ar^2 and stuff?

OpenStudy (anonymous):

yeah both mean the same

OpenStudy (anonymous):

SO I don't get how you are supposed to do this... I started factoring out things, but it's confusing...idk how to do...

OpenStudy (anonymous):

Let x be the first element and r be the common ratio x + r x + r^2 x = 73.5 x (rx)(r^2x)= 2744 You solve the two equations for x and r and you find two real solutions x=3.5 and r =4 or x=56 and r =1/4 Both yield the same 4 numbers. Notice that the second equation yields r x =14 so x =14/r 14/r + 14 + 14 r = 73.5 Which yields r=4 or r = 1/4

OpenStudy (anonymous):

uh...

OpenStudy (anonymous):

okay.....

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!