A capacitor stores energy of 1.25 J. If when it is connected by means of a switch to a 15-Ω resistor it discharges to half this value in 15 s. What is the initial voltage across the capacitor? Given That U: is the capacitor's energy C: is the capacitance R: is the resistance q: is the capacitor's charge
@Esraa are you here?
Yes
@ash2326
We are give initial energy as 1.25 J so we have \[\frac{1}{2} CV^2=1.25 \text{Joules}\] Do you agree with this?
Yeah
You know how a capacitor charged at a potential V, discharges through a resistor?
No
OK, Let's discuss this. It'll take sometime and I need one favor from you!!!
Sure, but plz can u summarize it I have a time limit
Ok, I'll try to do i ASAP Suppose I have a capacitor C farad with initial voltage V and it's connected with a resistor R. Capacitor will discharge through the resistor but it won't discharge instantly. It'll take some time. Do you agree with this?
Yes
|dw:1335849782125:dw| Let the voltage at any time t be V(t) note that just V is the initial voltage, Now the current flowing through the circuit at any time be I Now tell me what's the current through the capacitor ?
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