Question

a car initially going 50ft/sec brakes at a constant rate (constant negative acceleration), coming to a stop in 5 seconds
a) how far does the car travel?
b) how far does the car travel if it's initial velocity is doubled, but it brakes at the same constant rate

Answer 1

use that formula, \[s=ut+( ft ^{2})/2\]

Answer 2

when,s is the distance traveled . u is the initial velocity , t is time and f is acceleration..

Answer 3

here it is retardation , so you have to use negative sign

Answer 4

oh,sorry i forgot the first step.. use \[v=u-ft\]

Answer 5

here v=0 , you know the values of u and t.. so you will get f.. put it in the first equation

Answer 6

you did not get it?

Answer 7

calculus not physics dummy