Question

what is the value of k if point S(-4,k) and T(-1,0) are sqrt 73 ts apart

Answer 1

if THERE Are two points A (x,y) and B(m,n).. the distance between them is \[\sqrt{(x-m)^2+(y-n)^2}\]

Answer 2

you know the distance is 73, just put the values in the equation.

Answer 3

??/

Answer 4

\[\sqrt{(-4+1)^2+(k-0)^2}=\sqrt{73}\]

Answer 5

now, can you do it?

Answer 6

mmm imma try and get back at you thanks alot:)

Answer 7

welcome :)

Answer 8

i probably did it so wrong but is it 0+k2^+148

Answer 9

well,you square both sides .. you will get \[{(-3)^2+k^2}=73\]

Answer 10

\[so, 9+k^2=73\]

Answer 11

thats the answer

Answer 12

\[k^2=64 \]

Answer 13

so, k=8

Answer 14

\[\pm8\]