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Mathematics 7 Online
OpenStudy (anonymous):

SQUEEZE THEOREM........... when talking about SQUEEZE THEOREM, why we consider open interval only ? i will provide an image if any doubt in question.

OpenStudy (anonymous):

OpenStudy (anonymous):

WHY DON'T we take closed interval too ?

OpenStudy (anonymous):

somebody help me plz

OpenStudy (zepp):

The squeeze theorem states that if we have something like \[f(x) \le g(x) \le h(x)\] If \[f(x)\lim_{x \rightarrow a} = h(x)\lim_{x \rightarrow a}=L\] Then \[g(x)lim_{x \rightarrow a} = L\]

OpenStudy (anonymous):

hey zepp... i take a look at u have explained . :)

OpenStudy (anonymous):

yah.. u r right but when we write the theorem why we take only open intervals why not closed?

OpenStudy (zepp):

If not, there's not solution when x approches a.

OpenStudy (zepp):

What do you mean?

OpenStudy (anonymous):

i have sent an image took a look at that explanation.. .... can the intervals be closed?

OpenStudy (anonymous):

i got ur point . really thanks :) :) thanks a lot for helping :)

OpenStudy (zepp):

The interval doesn't really matter, we only want the value of y when something is approaching some value of x What it is trying to say is that in this interval that contain the point x, we have the limit of the functions. You are welcome :)

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