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solve: log5(x-2)+log5(x-5)=log5(10)
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do u mean base 5?
\[\log_{5}(x-2)+\log_{5}(x-5)=\log_{5}10 \]
x=0 , x=7 ok?
use the log/exponential property \[5^{\log _{5}(x)} = x\]
Boxman reply........
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boxaman tell us if u didnt understand
yah
sorry im reading through the book... supposed to solve using the one-to-one property...i know the answer is x=7
HINT: \[ (x-2)(x-5)=10 \]
log(a) + log(b) = log(ab) use this property
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one to one property if log(a) = log(b) --> then a=b
thank you all
Glad to help :)
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