Question

please help PLEASE
0=-16t^2+96t-140

Answer 1

factor and please show steps

Answer 2

first you can factor it out -2 ,yes ?

Answer 3

so than what will result ?

Answer 4

i need to know what happens to the 24

Answer 5

24 ? from what you have got it ?

Answer 6

\[\huge t=\frac{7}{2}\;\;\; or\;\;\; t=\frac{5}{2}\]

Answer 7

0= -4(4t^2-24t+35)

Answer 8

the 4 disappears

Answer 9

divide both sides by 4, 0 divided by 4 =0

Answer 10

yes i know but what is the next step ?

Answer 11

0= -4(4t^2-24t+35)

Answer 12

4t^2-24t+35= 0

Answer 13

ok but the 24 how do u factor that?

Answer 14

try this way
\[\Large 16\times(t-3)^2 -4=0\]

Answer 15

im confused

Answer 16

where?

Answer 17

at^2+bt+c=0 <-- compare this formula with urs, substitute the letters with the numbers and use this formula :

t= (-b+-squareroot(b^2 - 4ac)) / 2a

Answer 18

see when its factored out it turns into 0= -4(2t-5)(2t-7) so where does the 24 go? how does the 24 get factored?

Answer 19

u dont have to factor if the equation is too complicatted, so just use the formula

Answer 20

here check this tutorial out all the explainations are there

http://tutorial.math.lamar.edu/Classes/Alg/SolveQuadraticEqnsI.aspx

Answer 21

the quadratic formula always works, till now you'd probably finish it !!

\[\LARGE x_{1/2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a }\]

Answer 22

-16t^2+64t-28

Answer 23

okay first you need to simplify it a bit. Just see that all the coefficients are divisible by 4

you will get

-4t^2+24t-35

now you can see that there are no factors in whole numbers available for this equation.

now you need to use quadratic formula

\[-b \pm \sqrt{b^2 -4ac} /2a\]

Answer 24

so i dont have to factor i can just use the quadratic formula?

Answer 25

of course.

Answer 26

simply it is (2t-7)(2t-5)=0
so t=7/2
or t=5/2