Eight dipoles of charges of magnitude e are placed inside a cube.The total electric flux coming out of the cube will be....

Question

anonymous · Answer

the total electric fux=Qinside/epslon
but the Qinside =0 because each dipole has net charge zero(q+(-q)=0)..put this value and get your answer..it will be Zero..

anonymous · Answer

The electric field E exerts a force qE on charge +q and a force -qE on charge -q of the dipoles .since  these forces are equal and opp.,they add upto 0

anonymous · Answer

thnQ Taufique and guru ....

anonymous · Answer

@ gurvinder.. according to you...the net force is zero right but what is the relation ,you fond between net force and electric flux..

anonymous · Answer

see this 
net flux= flux coming+ flux out going
if we take flux coming is -ve flux out going is +ve
in this case flux coming = flux out going 
there fore net flux= 0

anonymous · Answer

swalah r u sure?

anonymous · Answer

100%

anonymous · Answer

Swalah is right neha because on the negative electric lines of force terminates and electric lines of forces start from positive charge ,it is clear from figure..
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due to same magnitude of charge ,the total out going electric lines of force through area will be  equal to total incoming lines of force.
hence net electric  flux=total outgoing  electric lines of force /total incoming lines of force 
                                 =zero