Question

here it is...

Answer 1

1/2 + 1/4 + 1/8 + (1/2)^k + (1/2)^k +1 = 1 - (1/2)^k+1
1 - (1/2)^k + (1/2)^k+1 = 1 - (1/2)^k+1

Answer 2

Is it two separate ones?

Answer 3

no just the consistent one..do you want me to type the whole thing out?

Answer 4

well, i dont understand your question..what's the whole question?

Answer 5

prove using mathematical induction:
\[\sum_{i=1}^{n} (1/2)^i = 1 - (1/2)^n\]

Answer 6

The series of numbers is:
1/2 + 1/4 + 1/8 + (1/2)^k= 1 - (1/2)^k

Showing for n=k+1
1/2 + 1/4+ 1/8 + (1/2)^k+1 = 1 - (1/2)^k+1
Using subsitution from assuming n = k ,
1 - (1/2)^k + (1/2)^k+1 = 1 - (1/2)^k+1
Where do we go from here..?

Answer 7

then assume \(n=k+1\)

Answer 8

lol i already did tat

Answer 9

tats tis part:
1 - (1/2)^k + (1/2)^k+1 = 1 - (1/2)^k+1

Answer 10

woops. normally you assume \(n=k\) first then \(n=k+1\)

Answer 11

oh i did both of them, just skipped n = k and subsituted it in later for a portion of n = k+1