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Mathematics 20 Online
OpenStudy (chrisplusian):

a general integration question

OpenStudy (chrisplusian):

i was given an inegration formula in a test review last night that concerns integration of a constant to a power\[\int\limits a^u du=(1/Lna) a^u+c\] I later found that the constant has to be positive and not equal to one. What do you do for the integration of a constant to a power when the constant is less than zero or equal to one?

OpenStudy (lgbasallote):

if less than zero..you uhhh..i dont think that's possible is it o.O

OpenStudy (mimi_x3):

Any examples?

OpenStudy (chrisplusian):

not sure of an example, just trying to reason out what i would do in the case that it was negative or equal to one

OpenStudy (chrisplusian):

Like when you use the general power rule for integration if the power of the exponent is negative one the rule doesn't apply, what do you do then? I have learned that you then use the natural log definition of 1/u du = lnabsikute valeu of u plus c

OpenStudy (mimi_x3):

A negative one do you mean like: \[\large\int e^{-2x+1} dx\]?

OpenStudy (lgbasallote):

e isnt -1 :P

OpenStudy (mimi_x3):

He said raised to the negative; \(-2x+1\) is negative. :P

OpenStudy (lgbasallote):

no he means when a is 1 or negative because ln of nega doesnt exist and 1/ln1 = undefined

OpenStudy (mimi_x3):

lol, woops; i read it wrongly. Are you able to give an example?:P

OpenStudy (chrisplusian):

in teh definition I was talking about the "a" so the constant could not be negative one or equal one. I truly haven't run into this situation, but I have had this professer three times and when she stresses a point, it is generally on the final. She stressed this rule even though we haven't been subjected to any of its content yet

OpenStudy (phi):

You would have to use complex numbers (with sqrt(-1) )

OpenStudy (chrisplusian):

ok thanks guys

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