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|(n+1)^(1/2) - n^(1/2)| = 1/((n+1)^(1/2) + n^(1/2)) Could someone explain this equality to me, having trouble. Thanks.
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\[ \sqrt{n+1}-\sqrt{n}=\frac{1}{\sqrt{n}+\sqrt{n+1}} \] No need for absolute value is the quantity is positive. Cross multuply and you get n+1 -n = 1 You are done
I was trying to work out how you produce the RHS having been given the LHS
Them tutors always like to make life difficult!
\[ \sqrt{n+1}-\sqrt{n}=\frac{\left(\sqrt{n+1}-\sqrt{n}\right ) \left(\sqrt{n+1}+\sqrt{n}\right)}{\sqrt{n+1}+\sqrt{n}}= \frac { n+1 -n}{\sqrt{n+1}+\sqrt{n}}=\\ \frac { 1}{\sqrt{n+1}+\sqrt{n}} \]
Perfect. Was just googling conjugate as we spoke. Thanks very much for your time.
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