Landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = -0.005x^2 + 0.41x - 5.1, where x is the horizontal distance of the rock, in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizontally from Landon will the rock land?

A. 66.71 ft

B. 33.35 ft

C. 15.29 ft

D. 7.65 ft

Question

Landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = -0.005x^2 + 0.41x - 5.1, where x is the horizontal distance of the rock, in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizontally from Landon will the rock land?

A. 66.71 ft

B. 33.35 ft

C. 15.29 ft

D. 7.65 ft

anonymous · Answer

you can read more about this in kinematic part of physics. However, you know that when the rock hits the earth, it's 5.1ft about the ground right? 
Y is the measurement of the height, which should be 5.1ft. Plug in and solve for x, which should be a quadratic eq. Good luck!

anonymous · Answer

above the ground*