Question

Simplify: i^36

Answer 1

the i parts are fun enough, they simplify to a remainder after you divide by 4

\[\text{when given: }i^n\text{, we want the remainder of }\frac{n}{4}=q+remainder.\]

\[i^n=i^r\]

Answer 2

i cant read that ):

Answer 3

neither can i :)

Answer 4

does 36/4 have a remainder?

Answer 5

i dont know... yes?

Answer 6

guessing doesnt promote understanding ...

36/4 = 9+0

i^36 = i^0

Answer 7

so if i remembered this right we just end up with i^0= 1

Answer 8

sorry but you were confusing me. i figured it out anyways. its 1. thanks.

Answer 9

'sok :)

Answer 10

didn't know about that method
you could also do
\[\large i^{36} = (i^{2})^{18} = (-1)^{18} = 1\]

Answer 11

36 = 0 mod 4 i think is the usual notation that I was thinking of

Answer 12

thank you, dumbcow! that was simple. appreciate the help.