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Mathematics 13 Online
OpenStudy (anonymous):

can you give me a problem that has a binomial which is NOT a factor of the polynomial being divided?

OpenStudy (chrisplusian):

can you explain what you are doing, or what you are trying to figure out?

OpenStudy (anonymous):

Suppose you divide a polynomial by a binomial. How do you know if the binomial is a factor of the polynomial? Create a sample problem that has a binomial which IS a factor of the polynomial being divided, and another problem that has a binomial which is NOT a factor of the polynomial being divided.

OpenStudy (anonymous):

i just need this and another problem that has a binomial which is NOT a factor of the polynomial being divided.

OpenStudy (chrisplusian):

ok a binomial is a factor that has two terms right? so if we said that (x-2) is one factor of the numerator and the other is (x-3). then you foil them to get\[x ^{2} -5x +6\] then just choose one of the original factors (eg. (x-2)) to be the denominator. then you could very easily do the second problem by making sure you don't include factors of the numerator in the denominator

OpenStudy (anonymous):

i have this equation for the first one (-6x^3 + x^2 + 13x + 6) ÷ (5 - 3x), i just am confused about how to make this into the second one.

OpenStudy (anonymous):

okay so basically what does (-6x^3 + x^2 + 13x + 6) ÷ (5 - 3x) look like not including factors of the numerator in the denominator?

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