Question

find the integral (4x^3+2/2x^4+4x+3) dx

Answer 1

\[\int\limits_{}^{}\frac{4x ^{3}+2}{2x ^{4}+4x+3}dx\]

Answer 2

I'm thinking a u-sub of u=2x^{4}+4x+3 will work, right?

Answer 3

my answer choices are \[2 \ln \left| 2x ^{4}+4x+3 \right|+C\] , \[\frac{-2}{(2x ^{4}+4x+3)^{2}}+C\] , \[1/2\ln \left| 2x ^{4}+4x+3 \right|+C\] , \[\frac{-1}{2(2x ^{4}+4x+3)^{2}}+C\]

Answer 4

we gotta try partial fraction

Answer 5

okay where do we go from there

Answer 6

It's actually a simple U-sub

Answer 7

its 3rd choice do you need to show work?

Answer 8

let u=2x^4 +4x + 3
evalute du, du = 8x^3 + 4 = 1/2 (4x^3 +2)
then the rest is a general natural log integral

Answer 9

are you sure it is the third choice? no i just need the correct answer

Answer 10

yep i used u substitution just like wattagwan

Answer 11

sweet thank you so much

Answer 12

no problem