Find the Derivative...
where karina
in the attached file
so my system is not allowing the file it has virus
ok hold on
Hopefully it doesnt say that is has a virus..
do you know the product rule and the quotient rule?
yeah but i get lost in the process
oh ok,, in this question u need to use them both first thing u do is\[\frac{d}{dx}(\frac{x^3+3}{(4x+3)(3x+2)})\]u take the derivative of the nominator and multiply it by the denominator then u take the derivative of the denominator and multiply it by the numinator and find the difference between them,, then divide the whole answer by the denominator squared \[\frac{d}{dx}=\frac{\frac{d}{dx}(x^3+3) \times (4x+3)(3x+2)- \frac{d}{dx}((4x+3)(3x+2)) \times (x^3+3)}{(4x+3)^2(3x+2)^2}\]
\[=\frac{3x^2(4x+3)(3x+2)-(4(3x+2)+3(4x+3)) )\times (x^2+3)}{(4x+3)^2(3x+2)^2}\]
notice that for the derivative of the denominator u need to use the product rule
ok
Oooh okay... gotcha :)
:)
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