Ammonia and gaseous hydrogen chloride combine to form ammonium chloride. NH3+HCL-NH4CL

if 4.21 L of NH3(g) at 27 C and 1.02 atm is combined with 5.35 L of HCL(g) at 26 C and 0.998 atm what mass of NH4Cl(s) will be produced? which gas is the limiting reactant? which gas is present in excess?

Question

Ammonia and gaseous hydrogen chloride combine to form ammonium chloride. NH3+HCL->NH4CL

if 4.21 L of NH3(g) at 27 C and 1.02 atm is combined with 5.35 L of HCL(g) at 26 C and 0.998 atm what mass of NH4Cl(s) will be produced? which gas is the limiting reactant? which gas is present in excess?

anonymous · Answer

PV = nRT
  
Find no. of mol of each gas by using the formula given above. Then the no.of mol multiply by the molar mass of the gas to find it mass.
Usually, the lower no of mol is the limiting reactant