Question

given that p and 1 are the roots of the quadratic equation x^2-(2k-3)x+3=0.
find the value of p and k.

b) given that the quadratix\c equation 4x^2-(8k-12)x-8k^2+6k+21=0 has two different real roots. find the range of values of k.

Answer 1

It has been a while since i have used these so I don't want to give you a wrong answer, I will try to get someone here that knows how to do it :P

Answer 2

ok

Answer 3

Maybe u can use following formula for sum and product of roots
sum = -b/a
product = c/a

Answer 4

@estudier I was just about to write that ^^

Answer 5

Sorry, u carry on then...

Answer 6

... lol It seems that I can't do it, I got stuck in a minus I'm deeply in doubt what to do ! @_@

Answer 7

\[\LARGE x^2+px+k=0\]
\[\LARGE x_1+x_2=-p\]
\[\LARGE x_1\cdot x_2=k\]

\[\LARGE x^2-(2k-3)x+3=0\]
\[\LARGE x_1+x_2=-p\]
\[\LARGE x_1+x_2=-(2k-3)\]
\[\LARGE -p=-(2k-3)\]
\[\LARGE p=2k-3\]


\[\LARGE x_1\cdot x_2=k\]
\[\LARGE x_1\cdot x_2=3\]
\[\LARGE k=3\]

\[\LARGE p=2k-3\]
\[\LARGE p=2*3-3\]
\[\LARGE p=3\]
so p=k

could it be?? ( I'M NOT SURE ABOUT THIS SOLUTION)
I have to go, see you later ...