Balance the following oxidation-reduction reactions, which take place in acidic solution, by using the "half-reaction" method. NO3-(aq) + Br-(aq) -> NO(g) + Br2(l)
How would i balanced nitrogen and oxygen NO3-(aq) -> NO(g)...?
what's an A-level i'm trying to balance equations on here..
\[(2Br^- \rightarrow Br_2+2e^-) \times 3\] \[(3e^-+4H^++NO_3 \rightarrow NO+2H_2O)\times 2\] ------------------------------------------------- \[6Br^- \rightarrow 3Br_2 +\cancel{6e^-}\] \[\cancel{6e^-}+8H^++2NO_3 \rightarrow 2NO+4H_2O\] --------------------------------------------------------
so would this be the correct answer..? 2NO3-(aq) + 8H+ +6Br-(aq) -> 2NO(g) + 4H2O + 3Br2(l)..? :P
i dont think it's right cause the equations don't balance on the right side its 2+8+6=16 and on the left side its 2+4+3=9
You say the charges? Left side is -6+8-2=0 Right side has no charges, 0
no the elements
No, you don't balance element by adding them, balancing element by element is the way.
OHH, so my answer is correct then? o:
yes
i mean you're answer lol
okay, ty!!! </333
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