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Evaluate the double integral of (y-2x^2)dA over R where R is the region bounded by the square |x|+|y|=1.
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Your square is the picture in the attached file It is bounded by the four lines \[(y=1-x,y=-x-1,y=x+1,y=x-1) \] It should be easy now to set up the integral.
Your in integral will be \[ \int _{-1}^0\int _{-x-1}^{x+1}\left(y-x^2\right)dydx+\int _0^1\int _{x-1}^{1-x}\left(y-x^2\right)dydx \] compute these two integrals, you will find them equals. Could you have predicted that?
I have 4 partitions :))
Only two.
Do I have to expand all these?
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No, you do integrate first with respect to y, then with respect to x
I got 2(1/2 -2/3)
-1/3
That is right.
YAAAAAAY! Thanks! You're a genius! :)
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yw
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