Determine if the following function is concave up or down in the first quadrant. y=4x^3/5
concave up get the second derivative
how do u do it?
it was concave down
derivatives are a calculus term that lower maths dont have a concept of yet so its important to know what level you are at
\[y=\frac{4}{5}x^3\implies y'=\frac{12}{5}x^2\implies y''=\frac{24}{5}x\]
i don't understand that at all what is this called so i can look it up on youtube?
It follows that\[\frac{24}{5}x>0\]whenever \(x>0\).
prior to calculus, you learn about elementary graphs of even and odd functions
You are being asked this kind of questions and you don't know what it is?
no i dont ... lol im bout to go study it now
Do you know what a derivative is?
well i know the definition but not the math problem
If you know the definition, then you know how to apply it, stretch it, bend it and use it to solve your problems.
do u kno of a way where i can do this on a graphing calculator
It's much tougher to learn how to do this particular problem on a graphing calculator than it is by looking at it for five seconds.
so i cant do it by plugging it into the y= and then trace?
http://tutorial.math.lamar.edu/Classes/CalcI/DiffFormulas.aspx Sorry about a while ago. I got confused.
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