Choose the point-slope form of the equation below that represents the line that passes through the points (−3, 2) and (2, 1). y+3=-5(x-2) y-2=-5(x+3) y+3=-1/5(x-2) y-2=-1/5(x+3)
Your first step would be to find the slope. Do you know how?
y2-y1/ x2-x2?
x1*
Yep. Then you can plug the slope into m in the point-slope equation: \[y-y_{1}=m(x-x_{1})\]
Wait... huh?
so whatever you get as the slope goes into the "m" position. You need one point, either (-3,2) OR (2,1) for the y1 and x1 values
I got 4 for the slope.
OK, now use (-3,2) for the x1 and y1 values. It looks like the answer will be based on that point rather than (2,1) (fyi, but when you simplify them they're the same) .
y-1=4(x-2)?
yeah, that's right but looks like the answer choices want you to use (-3,2)
?
y-2=m(x--3) which is y-2=m(x+3) might want to check your slope.
...... I'm so lost.
sorry! :( [slope]=m=(1-2)/(2--3)=(-1)/(2+3)=-1/5
So slope= -5
no slope is -1/5
oh
sorry for misleading you by not checking it myself earlier ~ so now, using (-3,2) as (x1,y1)\[y-2=-{1 \over 5}(x+3)\]
It's fine. Thank you for he help
sorry it took so long. hope it helped at least a little.
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