Question

sandy has a black hat in her closet. she also has a red shirt, a blue shirt, and a purple shirt. sandy has green pants and orange pants. how many different combinations can sandy make. how do i figure this out and explain please. thanks,

Answer 1

(Number of ways to do first thing) * (Number of ways to do second thing) = number of ways to do BOTH things.

How many hat options does she have? How many shirt options? How many pants options?

Answer 2

am i correct to say 3 (shirts) x 2 (pants) =6 combinations

Answer 3

Here's a similar problem. Suppose I flip a coin and roll a die. How many possible outcomes could I get?

Well, I could get 6 different possibilities from rolling the die. 1,2,3,4,5,6. For each of those possibilities, I could flip heads or tails. So my possibilities are:
1 & heads
1 & tails

2 & heads
2 & tails

3 & heads
3 & tails

4 & heads
4 & tails

5 & heads
5 & tails

6 & heads
6 & tails

6 possibilities for the first thing. 2 for the second. 6 groups of 2.
6*2 = 12 possibilities.

Answer 4

Correct for shirts and pants =D

Answer 5

And I believe you're meant to assume the hat options are simply "hat" or "no hat"

Answer 6

she has one hat

Answer 7

Okay, so the problem doesn't say, but it matters whether these are considered different outfits: