Question

Probability Problem for stats. Chart attached in comments..

Answer 1

Apply binomial:
P(x= 0) = .59^3
P(x=1) = 3C1 *.41 * (.59)^2
....
Can you continue!

Answer 2

I'm still really confused... ha /: I calculated those out and got .205 and .428 but I'm still not sure how you came up with those.

Answer 3

Sample space ={ GGG,GGB, GBG, GBB. BGG, BGB, BBG, BBB)
You need to figure out the probability for each element of the sample space.
P(GGG) = (.41)(.41)(.41) = .068921
P(GGB) = (.41)(.41)(.59) = .099179 --> If prob of girl is .41, the prob of boy is 1 - .41 = .59.
Now, you do the remaining 6 probabilities and post here.
Then, they can be entered into the chart, the mean found, and then the standard dev.
It is now time for you to find the Probability of (GBG).

Answer 4

@smicatrotto --> We can do this problem.

Answer 5

Okay.. I'm still confused on how you got .41 though.

but would it be:
GBG: .099179
GBB: .142721
BGG: .099179
BGB:.142721
BBG: .142721
BBB: .205379

Answer 6

I got the .41 from the problem you uploaded.

Answer 7

Okay, now let's count the sample space elements that have zero girl, one girl, two girls, and then three girls. Plus, we need the associated probabilities.

Answer 8

Zero Girls - 1 way
BBB: .205379
-------------------
One Girl - 3 ways
GBB: .142721
BGB:.142721
BBG: .142721
-----------------
Two Girls - 3 ways
P(GGB) = (.41)(.41)(.59) = .099179
GBG: .099179
BGG: .099179
=================
Three Girls - 1 way

P(GGG) = (.41)(.41)(.41) = .068921

Answer 9

Wait, I figured it out!! There was a help button on my homework and it walked me through it. Thank you SOOO much for your help though, I appreciate it :)

Answer 10

@smicatrotto --> Did you get the mean and the standard deviation?

Answer 11

Yeah it explained that too!

But I have a different one that is the same problem except different numbers... it looks like this. I'm having problems with the std deviation.

Answer 12

I got .50 but it says it's wrong... /:

Answer 13

Alright, I figured it out. It's .084

Could you help me with this one too?

Answer 14

1) Have you clicked on the help button? If so, what was the hint?
2) Do you know about binomial probabilities?

Answer 15

Well when you click the help button it changes the problems/numbers so I don't want to do that for this one ha, but no, these confuse me sooo much /: Like this whole chapter, I'm so lost ha.

Answer 16

See, I don't want to start the problem and then be told no help is needed. So, that's why I asked.

So, we'll start the problem.

Answer 17

@directrix Oh, right. I'm so sorry about that /:

Answer 18

Probability (Headache) = .196
Probability (No Headache) = .804

Agree?

Answer 19

Yes, that makes sense

Answer 20

So, add the two probabilities that correspond to exactly 4 headaches and exactly 5 headaches respectively. That should be the answer.

Answer 21

Okay, so .0062

Answer 22

Wow, that was so easy... haha it was right! Thank you!!

Answer 23

That's what I got. Great.