Question

Suppose that triangle ABC is similar to triangle DEF with AB = 20, BC = 8, AC = 19, and EF = 12. Find DE and DF.

Answer 1

Lengths of corresponding sides of similar triangles are in proportion.
The similarity statement triangle ABC is similar to triangle DEF gives that AB/DE = BC/EF = AC/DF.
So,
20/DE = 8/12 = 19/DF

The scale factor is 8/12 or 2/3.

20/DE = 8/12

8 (DE) = 12*20

DE = 12*(20/8)

DE = 30
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Your turn now:

Find DF by solving:

8/12 = 19/DF

Post answer here for free check.

Answer 2

27=df

Answer 3

@1dpp --> Check my work and yours, too.

19/DF = 8/12
8 DF = 19*12
DF = (19*12) / 8
DF = 28.5

Answer 4

I saw what i did. i made a silly mistake and multiplied 18*12
smh.. Thanks