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Improper integrals
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\[\int\limits_{0}^{1}\ln( e x)\]
I am not sure why you would use improper integrals when one of the domain is a constant
you should memorize the anti derivative of \(\ln(x)\) because it is very common. otherwise you have to do a rather simple integration by parts, but the anti derivative is \[x\ln(x)-x\] in your case you have to adjust for the constant
oh it is improper because the log is not defined at 0 it goes to minus infinity there
btw don't forget that \[\ln(ex)=\ln(e)+\ln(x)=1+\ln(x)\]
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so you have \[\int_0^1dx+\int_0^1\ln(x)dx=1+\int_0^1\ln(x)dx\]
So the answer is 1?
0
@satelite73 Why did you use integration by parts?
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