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Mathematics 7 Online
OpenStudy (anonymous):

An indexed set of vectors { v1,v2,...,vp} is linearly dependent if

OpenStudy (unklerhaukus):

one of them can be made by combinations of the others

OpenStudy (anonymous):

And by combination you mean elementary row operations.

OpenStudy (anonymous):

Can anyone give me an example. That would be helpful.

OpenStudy (amistre64):

v1 = 1,2 v2 = 2,4

OpenStudy (anonymous):

Well yeah because they are multiples of each other.

OpenStudy (anonymous):

I can cancel one and have the zero vector.

OpenStudy (amistre64):

right, so they are actually both on the same line and one is dependant on the other in that regards; you can create one from a combonation of the others

OpenStudy (amistre64):

3 vectors in a plane are linearly dependant since it only takes 2 vectors to reach every point 4 vectors in a cube are dependant since 3 vectors can reach every point in a cube etc

OpenStudy (anonymous):

Oh ok so as long as I can create a zero vector with the given vectors or if there is already a zero vector in the set I can say that the set of vectors are dependent.

OpenStudy (anonymous):

Is this the only rule?

OpenStudy (amistre64):

i wish it was the only rule; there is like a dozen of them that all really amount to the same thing said in a dozen different ways

OpenStudy (anonymous):

Yeah I hear my prof said a couple but then I realized it led me to the same conclusion so I was just trying to make sure.

OpenStudy (amistre64):

if the determinant = 0; its dependant if the row reduction echelon form has a row or column of zeros; its dependant if the the trivial solution is not the only solution to the zero vector, its dependant ....yada yada yada

OpenStudy (anonymous):

oh i see lol @amistre64 If there is a zero row or vector and you have it in triangle form then the determinant will be zero. I see how things kind of repeat itself.

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