An indexed set of vectors { v1,v2,...,vp} is linearly dependent if
one of them can be made by combinations of the others
And by combination you mean elementary row operations.
Can anyone give me an example. That would be helpful.
v1 = 1,2 v2 = 2,4
Well yeah because they are multiples of each other.
I can cancel one and have the zero vector.
right, so they are actually both on the same line and one is dependant on the other in that regards; you can create one from a combonation of the others
3 vectors in a plane are linearly dependant since it only takes 2 vectors to reach every point 4 vectors in a cube are dependant since 3 vectors can reach every point in a cube etc
Oh ok so as long as I can create a zero vector with the given vectors or if there is already a zero vector in the set I can say that the set of vectors are dependent.
Is this the only rule?
i wish it was the only rule; there is like a dozen of them that all really amount to the same thing said in a dozen different ways
Yeah I hear my prof said a couple but then I realized it led me to the same conclusion so I was just trying to make sure.
if the determinant = 0; its dependant if the row reduction echelon form has a row or column of zeros; its dependant if the the trivial solution is not the only solution to the zero vector, its dependant ....yada yada yada
oh i see lol @amistre64 If there is a zero row or vector and you have it in triangle form then the determinant will be zero. I see how things kind of repeat itself.
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