Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

prove that sinhx greater than zero

OpenStudy (anonymous):

prove that sinhx>o

OpenStudy (anonymous):

solution to that

OpenStudy (anonymous):

do you want the solution to set to where sinhx > 0 or prove that sinhx >0 (as stated in your post) ? because the latter is false...

OpenStudy (anonymous):

prove that sinhx>0

OpenStudy (anonymous):

hyperbolic function

OpenStudy (anonymous):

pls save me out i av exam on saturday

OpenStudy (anonymous):

is there a domain restriction because sinhx < 0 for x < 0. yes, hyperbolic function sinhx = (e^x - e^-x)/2.... this function is negative for x<0. if you want to prove that sinhx > 0 for x>0, then just do it normally...

OpenStudy (anonymous):

as you can see from the almighty wolfram, sinh(x) is negative for x<0... http://www.wolframalpha.com/input/?i=graph+sinh%28x%29

OpenStudy (anonymous):

pls i dont understand it

OpenStudy (anonymous):

ok... don't worry.... it's eaier than you think....

OpenStudy (anonymous):

***easier***

OpenStudy (anonymous):

let's get the question correct first: the question is to prove that sinhx > 0 for all x or for x>0 ?

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

\[x > 0\]

OpenStudy (anonymous):

in hyperbolic function

OpenStudy (anonymous):

hyperbolic sinh(x).. ok.

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

btw... don't let the name hyperbolic function scare you... all it is is an exponential function -- one of the easiest functions to work with in calculus...

OpenStudy (anonymous):

let f(x) = sinh(x). so first we need to find the zero(s) of f...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

the zero for f occurs at x=0 only... lemme know if you need any clarification here... |dw:1336027061124:dw||dw:1336027182119:dw||dw:1336027240452:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!