prove that sinhx greater than zero
prove that sinhx>o
solution to that
do you want the solution to set to where sinhx > 0 or prove that sinhx >0 (as stated in your post) ? because the latter is false...
prove that sinhx>0
hyperbolic function
pls save me out i av exam on saturday
is there a domain restriction because sinhx < 0 for x < 0. yes, hyperbolic function sinhx = (e^x - e^-x)/2.... this function is negative for x<0. if you want to prove that sinhx > 0 for x>0, then just do it normally...
as you can see from the almighty wolfram, sinh(x) is negative for x<0... http://www.wolframalpha.com/input/?i=graph+sinh%28x%29
pls i dont understand it
ok... don't worry.... it's eaier than you think....
***easier***
let's get the question correct first: the question is to prove that sinhx > 0 for all x or for x>0 ?
hello?
\[x > 0\]
in hyperbolic function
hyperbolic sinh(x).. ok.
yes
btw... don't let the name hyperbolic function scare you... all it is is an exponential function -- one of the easiest functions to work with in calculus...
let f(x) = sinh(x). so first we need to find the zero(s) of f...
ok
the zero for f occurs at x=0 only... lemme know if you need any clarification here... |dw:1336027061124:dw||dw:1336027182119:dw||dw:1336027240452:dw|
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