Question

\[f(x)=\frac{(x-1)(x-2)}{x-a},\ for\ x\neq a\] takes all values in \[+\infty ,-\infty\], then what is the interval where \[a\] lies?

Answer 1

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Answer 2

The range of f(x) has to be [\ (+\infty,-\infty)\]. Its not given whether a>x or a<x. I wrote the whole question.