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Mathematics 19 Online
OpenStudy (anonymous):

How do I solve this IVP problem. http://i.imgur.com/MJ62T.jpg

OpenStudy (anonymous):

Oh yeah \[\beta\] is postive constant

OpenStudy (anonymous):

Just wondering do I divide by t^2

OpenStudy (anonymous):

Yes, you should divide it by \(t^2\).

OpenStudy (anonymous):

\[x'(t) = \frac{x(t)}{t} + \frac{\beta \left(x(t)\right)^2}{t^2}\] Substitution should work.

OpenStudy (anonymous):

\[x(t) = vt \implies x'(t) = v't + v\]

OpenStudy (anonymous):

I hope you can do it from here.

OpenStudy (anonymous):

Would it not be x(t)/t^2

OpenStudy (anonymous):

No, try to think about it. *See the ODE*

OpenStudy (anonymous):

I dont really understand, Initially I thought that I divided both terms by \[t^{2}\]

OpenStudy (anonymous):

\[t^2 x'(t) = x(t) ( t +\beta x(t))\]Now divide by \(t^2\).

OpenStudy (anonymous):

\[x'(t)=x(t)/t*(\beta x(t))\]

OpenStudy (anonymous):

No wait

OpenStudy (anonymous):

\[t^2 = tx(t) + \beta (x(t))^2\]

OpenStudy (anonymous):

Oh wait I get it now, thanks!

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