What is the formula of magnetic field (vector form)?

Question

anonymous · Answer

is this a vector @AravindG?

aravindg · Answer

srryy.. B is magnetic flux dnsity and is a vector

aravindg · Answer

B = μH, where B is the magnetic flux density, H is magnetic field density and μ is the permeability of the medium

anonymous · Answer

$$mu i.dl*r/4pi |r^3|$$

anonymous · Answer

it is a vector in the direction of dl(cross product)r

marco26 · Answer

$$B=\frac{F}{qvsin \theta}$$

anonymous · Answer

$$B=(mu0/4pi)*\int\limits_{a}^{b}(I*(dl X r ))/R*R$$

here I is the current
dl is the segment of the current element
a,b are the limits of integration
r is unit vector
R is the distance of the point fro the current element

anonymous · Answer

@krishnakumar123 @marco26 @cibychak @AravindG Do you guys have all the same answer? I also got an answer that's not in the form like anyone of you. I found it here: http://teacher.pas.rochester.edu/phy122/Lecture_Notes/Chapter23/Chapter23.html#Heading3 formula (23.2) Kindly check please. Thanks!

anonymous · Answer

formula 23.2 relates to superposition of electric forces it is not related to the magnetic field.

anonymous · Answer

@krishnakumar123 Is it related to the electric field? I'm so not into this topic but I have to figure it out. I'm sorry. 

The problem is I'm given two oppositely charged particle and one that is positive. I need to find the vector defining its movement.

anonymous · Answer

The particles will move toward each other.So,the vector defining its movement will be the one that joins the centers of the two charges.So it should be { R1 vector - R2 vector },assuming the position vectors of the charges q1 ans q2 be R1 and R2 :)

anonymous · Answer

Sorry sorry. I got my answer from 23.10 not 23.2 :) Kindly check again. And here's an illustration of what I'm trying to say: http://en.wikipedia.org/wiki/File:VFPt_charges_plus_minus_thumb.svg

anonymous · Answer

I don't know what troubles you this much.if its a qualitative question just answer that the particles move along the vector joining the two charges.

anonymous · Answer

If you have to write the vector,the answer is just r vector

anonymous · Answer

It's an assignment. I have to write an equation.

anonymous · Answer

if you are having two oppositely charged particles, then the magnitude of the force between them is $$F=(q1*q2)/(4*3.14*8.854e-12*r*r)$$
and the force is a negative force and the two charges attract each other with this amount of force. The force may be visualized as|dw:1336116816118:dw|

The negatively charged one is attracting the positive charge and by the newton's 3 rd law also due to the reaction, the negative charge move towards the positive charge.