Question

2=1 proof

Answer 1

http://9gag.com/gag/689049

Answer 2

..and welcome to open study :)

Answer 3

Given x = 1 and y = 1, then

x = y

Multiplying each side by x,

x2 = xy

Subtracting y2 from each side,

x2 - y2 = xy - y2

Factoring each side,

(x + y)(x - y) = y(x - y)

Dividing out the common term, (x - y) results in

x + y = y

Substituting the values of x and y,

1 + 1 = 1

or

2 = 1

Answer 4

Such a proof does not exist. With all respect to shruti, you supposed that x = 1 and y =1. Later on, you divided both sides by (x-y). But, if x = 1 and y = 1, then (x-y) = 0. In mathematical proofs, dividing both sides by 0 is not allowed.

Answer 5

This is not true. If you are multiplying both sides by x, then you have to exclude the fact that x could be zero. You should never divide or multiply both sides of an equation by a variable.

Answer 6

4