When Ayla improves her game of darts the chances that a she hits a bullseye is 0.65.
Assume that each throw is independent.

What is the probability that at least one will hit?
What is the probability that 2 will hit?

Question

When Ayla improves her game of darts the chances that a she hits a bullseye is 0.65.
Assume that each throw is independent.


What is the probability that at least one will hit?
What is the probability that 2 will hit?

daenio · Answer

@satellite73

anonymous · Answer

you need number of attempts for this one

anonymous · Answer

how many times does she throw?  then we can use the binomial to solve

anonymous · Answer

This totally depends on how many times she throws.
No Kidding

anonymous · Answer

we could solve it with $n$ but i doubt that is what the quesion is asking 
if she throws 4 times then the probability she hits exactly two is 
$$P(X=2)=\dbinom{4}{2}(.65)^2(.35)^2$$ for example

anonymous · Answer

that is "two bulls eyes, two not bulls eyes, and $\dbinom{4}{2}=6$ different arrangements of that outcome

anonymous · Answer

how many attempts??

daenio · Answer

When Ayla improves her game of darts the chances that a she hits a bullseye is 0.65.
Assume that each throw is independent.
What are the chances that three darts fired in succession will all hit bullseye?
What is the probability that none will hit?
What is the probability that at least one will hit?
What is the probability that 2 will hit?

anonymous · Answer

Ahhhhh 3 darts!!!!!

anonymous · Answer

ok three in a row is easy enough, since they are independent multiply the probabilities together and get $(.65)^3$

anonymous · Answer

none will be hit, means misses all three times. probability she hit is .65, probability she does not hit is 1 -.65 = .35, misses 3 times in a row is $(.35)^3$

anonymous · Answer

at least one means not none. since the previous question asks for none, once you get that answer subtract it from one. in other words find $1-(.35)^3$

anonymous · Answer

and finally two hit, gets two, misses one get $3\times (.65)^2(.35)$
the 3 is because she could miss the first, the second or the third, so three ways to do it

daenio · Answer

Thank you very much! :)

daenio · Answer

If you don't mind I have one more question.

12.	


The following table shows the points scored each game by Pat during the basketball season.
[1]	a)	What is the probability Pat scores between 10 and 15 points in a game?
[1]	b)	What is the probability Pat scores 16 or more points?
[2]	c)	This is an example of ___________ probability. Give reasons for your answer.
	   Points	            Frequency
               0-9	                  1
              10-15               	6
              16-20                	5
                21-25	       17
                  25+	          8

daenio · Answer

@satellite73

daenio · Answer

@FoolForMath