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If 2.1 moles of CaCl2 are dissolved in enough water to make a 0.92-liter solution, what is the resulting molarity? Answer 2.3 M CaCl2 0.44 M CaCl2 0.70 M CaCl2 3.0 M CaCl2
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concentration is the ratio of moles of solute per liter of solution: \[M = \frac{mol\space solute}{L\space solution}\] plug and solve
2.3?
2.3M
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