Question

A lady reaches her office 20 minutes late by traveling at a speed of 20 kmph and reaches I5 minutes early by traveling at 30 kmph. By how much time will she be early or late if she travels at 25 kmph.

Answer 1

Please help @Hero .

Answer 2

hmm do u know what fomrula u have to use?

Answer 3

I don't think there's any formula. You just have to use linear equations right?

Answer 4

hmm let me think abt this one

Answer 5

Perhaps distance = speed * time.

Answer 6

well we dont know the time we just know how late they came

Answer 7

How long will you be online?

Answer 8

ummm idk depends how bored i get

Answer 9

Can you do me a favour, if anything strikes to you about it, answer it will you? I'll have to leave now and I'll give you a medal the next time I come online ..

Answer 10

hahhah dont worry abt it. i want the answer for myself. This question is annoying me

Answer 11

distance = rate *time
y=20(x+(20/60))
y=30(x-(15/60)
20(x+(1/3)=30(x-(1/4))
20x+(20/3)=30x-(15/2)
10x=(85/6)
x=(17/12)
y=35
35=25((17/12)+z))
z=-(1/60)
which is one minute early.
Like i skipped some steps
If u have a problem with this or need an explanation like ask and when i come back on i will explain it to u

Answer 12

Let t be the amount of time to be "on time". Solve the following for t.\[20\left(t+\frac{20}{60}\right)=30\left(t-\frac{15}{60}\right)\]\[t=\frac{17}{12} \text{ hours}\]From the LHS of the equation, one can determine the distance.\[d=20\left(\frac{17}{12}+\frac{20}{60}\right)=35\text{ km} \]Have to break off for an appointment now. Back later.

Answer 13

yes bu then u gotta figure out how late or early the lady wld be if she drove 25 km /hr

Answer 14

To continue.

From the following expression, the lady will take 35/25 hours to travel 35km to her office @ 25 km/hr.\[t\text{ =}\frac{d}{r}=\frac{35}{25}\text{hours}\]Subtract the "on time" time, 17/12, from 35/25 the time taken @ 25 km/hr. If the difference is positive the lady was "late", took too long, otherwise, the lady was "on time" or "early".\[\frac{35}{25}-\frac{17}{12}=-\frac{1}{60}\text{hours} \]The lady was one minute early @ 25 km/hr.

Answer 15

YA :DDDD