Use the quadratic formula to find the roots of the equation. Round to tenths if necessary. 3x^2 - 4x - 8 = 0
A. {-1.7, 2.8}
B. {-2.8, 2}
C. {-1.1, 2.4}
D. no real solution

Question

Use the quadratic formula to find the roots of the equation. Round to tenths if necessary. 3x^2 - 4x - 8 = 0
A. {-1.7, 2.8}
B. {-2.8, 2}
C. {-1.1, 2.4}
D. no real solution

anonymous · Answer

you have a equation in the form ax^2 + bx + c = 0. The quadratic equation is $$\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$. Just plug in a, b, and c in and simplify

anonymous · Answer

^_- huh

anonymous · Answer

In the equation 3x^2 - 4x - 8    a=3   b=-4  c=-8  just plug those numbers into the formula and simplify

anonymous · Answer

−4±-4^2-4 (-4)(3)(8) − − − − − − −  √  2a

amistre64 · Answer

dont forget you a spot in the denominator

amistre64 · Answer

the latex format doesnt copy paste to well does it :)

anonymous · Answer

no

amistre64 · Answer

-b +- sqrt(b^2 - 4ac)
-------------------
            2a


that +- is notation for 2 separate formats; the are identical except for one has a + there and the other a -

a +- b means: a+b  and a-b

anonymous · Answer

And its -b in the front so it would be - (-4) in the beginning

anonymous · Answer

Ok you have both lost me

anonymous · Answer

$$\frac{-(-4) \pm \sqrt{(-4)^2 - 4(3)(-8)}}{2(3)}$$

anonymous · Answer

I just plugged a, b and c into the formula. All you have to do is simplify