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32^-3/5
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\[32^{-3/5}\]
1/8 is the answer. Which is 1/((32^(3/5))
First step, since it's a negative exponent, put it on the bottom of a fraction: \(\dfrac{1}{32^{3/5}}\) Second step, rewrite it with whole exponents: \(\dfrac{1}{\sqrt[5]{32}^{3}}\) Third step, calculate :)
How would I calculate that?
Well, I would start with \(\sqrt[5]{32}\). 32 should look kind of familiar, because it's a power of 2. Most of the time in these kind of problems, they won't give you really ugly calculations, so it's a safe bet that 32 will be the 5th power of something, and if we calculate \(2^5\), sure enough, we end up with 32. So that means \(\sqrt[5]{32}=2\). Then you just calculate \(\dfrac{1}{2^3}\).
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ohhh I understand thank you!! :D
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