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Mathematics 7 Online
OpenStudy (anonymous):

Factorise 2x-6

OpenStudy (anonymous):

Do you know how to find the greatest common factor?

OpenStudy (anonymous):

I vaguely remember how to

OpenStudy (anonymous):

Okay, it's easy. You just need to list all the prime factors of the expression's terms. Your expression has a 2 and a 6. So, let's list the prime factors. 2: 2 6: 2 3 Now, we need to find the factor in common between the two terms. In your expression, it's 2. And since your second term (-6) doesn't have an x, the GCF is simply just 2. Do you know what to do now?

OpenStudy (anonymous):

Slightly, I understand how to find the GCF now, so is the answer just 2, or is there more to it?

OpenStudy (anonymous):

There's more to it. :D We need to put the GCF on the left side of a set of parenthesis. 2( ) Remember your original expression, 2x-6. You need to put a binomial in the parenthesis that would multiply by 2 to equal 2x-6. So 2 times what equals 2x? And then 2 times what equals -6?

OpenStudy (anonymous):

Ahh, so is it 2(x-3)? or have I got it wrong?

OpenStudy (anonymous):

No, that's perfect! And there's your answer :D

OpenStudy (anonymous):

Thank you very much for the help! :D

OpenStudy (anonymous):

No problem! :D

OpenStudy (anonymous):

Okay, one more question, how do I factorise 2x(squared)+8x? I don't really understand how to factorise a square number, when there is a none squared number along with it. If that makes any sense at all..

OpenStudy (anonymous):

You're trying to factor \[2x^2+8x\] correct?

OpenStudy (anonymous):

That's correct

OpenStudy (anonymous):

would it be x(x+4)?

OpenStudy (anonymous):

Okay, so we will start by solving this one the same way. You have 2 and 8. Let's list the prime factors. 2: 2 8: 2 2 2 Since 2 and 8 both have a "2" in common, we use that in our GCF. This one is different from your first problem, since both of your terms have one "x" in common. But since they do, we can add x our 2. So the GCF is 2x. 2x( ) Can you factor it out now? You're close, by the way! :D

OpenStudy (anonymous):

2x(x+4)?

OpenStudy (anonymous):

Yeah! :D

OpenStudy (anonymous):

Woohoo! Yet again, thank you very much! :D

OpenStudy (anonymous):

You're welcome.. if you need help with anything else, just let me know. :D

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