Use the quadratic formula to find the zeros of the function. Round to tenths if necessary. y = 3x^ + 5x
A. {-2.23, 1.7}
B. {-1.7, 0}
C. {-2.8, 1.7}
D. no real solution

Question

Use the quadratic formula to find the zeros of the function. Round to tenths if necessary. y = 3x^ + 5x
A. {-2.23, 1.7}
B. {-1.7, 0}
C. {-2.8, 1.7}
D. no real solution

ash2326 · Answer

@PsYcHoEmOmAtH Do you know the quadratic formula?

campbell_st · Answer

this is the formula

for a quadratic f(x) = ax^2 + bx +c

$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

in your question a = 3 and b = 5 and c = 0

substitute the values then evaluate to find the zeros

anonymous · Answer

I know that I got lost though*

campbell_st · Answer

4ac will dissapear as 4 x 3 x 0 = 0

you will be left with

$$x = \frac {-5\pm \sqrt{5^2}}{6}$$

so the 2 solutions are 

$$x=\frac{-5 - \sqrt{25}}{6}$$

and 

$$x=\frac{-5+\sqrt{25}}{6}$$

just evaluate these for the zeros