How many liters of water vapor can be produced if 13.3 liters of methane gas (CH4) are combusted, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem.

CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)

Question

How many liters of water vapor can be produced if 13.3 liters of methane gas (CH4) are combusted, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem. 

CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)

anonymous · Answer

look at the ratio.
For every 1 molecule of methane that's combusted, 2 vapour molecules are produced.
1:2
thereore
13.3 L : 26.6 L of water vapour

anonymous · Answer

show work:
13.3L CH4*(1mole CH4/22.4 L CH4)*(2 mol H2O/1mol CH4)*(22.4L H2O/1mol H2O) = 26.6L H2O

22.4L /mol is for gas at standard conditions