Question

4 = 8(1-1.03^n)

Solve for n

Can you give me steps too?

Answer 1

is it
\[4=8(1-(1.03)^n)\]?

Answer 2

Yes Satellite73

Answer 3

I was told the answer is a nice 2 digit number

Answer 4

ok, to solve this problem, you first need to both sides by 8. After this the equation will look like this.
\[.5=(1-1.03^n)\]
now, you can subtract the 1 from both sides
-.5=-1.03^n
Now take the natural log, ln, of both sides. This will give the following.
ln(.5)=n*(ln(1.03))
divide ln(.5) by ln(1.03) and there is your answer!

Answer 5

divide by 8, subtract 1 get
\[-\frac{1}{2}=-(1.03)^n\] or
\[\frac{1}{2}=(1.03)^n\]
then what delta said

Answer 6

its not a nice number, i got -23.45
double check me though

Answer 7

although i would recommend knowing that to solve for
\[b^x=A\] you can go right to
\[x=\frac{\ln(A)}{\ln(b)}\] by the "change of base" formula

Answer 8

Satellite73 I was told the resulting equation should be an exponential equation in the from
\[m ^{x} = n\]

Answer 9

and indeed it is

Answer 10

I was also told to use trial and error to find the value of n.

Answer 11

\[(1.03)^n=.5\]

Answer 12

really? well try it then but i would solve using logs

Answer 13

Crap this is really confusing and it is the very last question of my unit on Geometrics