Question

int_{4}^{2}=-int_{1}^{4}-int_{0}^{1}+int_{0}^{2}

Answer 1

well this is the original question .. Assuming that ∫[0,1,,] f(x)dx=3 ∫[0,2] f(x)dx=5 ∫[1,4] f(x)dx=8 What is ∫[4,2] f(x)dx?

Answer 2

and im not sure how to go about solving it

Answer 3

\[
\int_0^1f(x)dx=3, \int_0^2f(x)dx=5, \int_1^4f(x)dx=8, \int_4^2f(x)dx=?
\]
Is that the problem? If so:
\[
\int_4^2f(x)dx=-\int_2^4f(x)dx=-\left( \int_1^4f(x)dx+\int_0^1f(x)dx-\int_0^2f(x)dx \right)
\]

Answer 4

So yeah, you were correct, I just misunderstood what you were saying.

Answer 5

now how do i solve that part

Answer 6

Just substitute in the numbers that it told you each of those integrals were equal to.

Answer 7

so i plug in 3 to the first integral? a

Answer 8

You plug in 3 for \(\int_0^1f(x)dx\), etc.

Answer 9

thanks