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OpenStudy (anonymous):
the point (13,5) lies on the graph of 2log base b x. the value of b is
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OpenStudy (anonymous):
@mertsj can u help me?
OpenStudy (anonymous):
\[2\log_{b} x\]
OpenStudy (anonymous):
can u help me with one more question after that? please?
OpenStudy (anonymous):
\[\log_{3b} t=M\] given this equation solve for b and give answer inexponential form?
OpenStudy (mertsj):
\[2\log_{b}x=y \]
\[\log_{b}x^2=y \]
\[b^y=x^2\]
\[b^5=13^2\]
\[(b^5)^{\frac{1}{5}}=(13^2)^{\frac{1}{5}}\]
\[b=13^{\frac{2}{5}}\]
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OpenStudy (mertsj):
I hope that's right. Do you spot any errors?
OpenStudy (anonymous):
i think its right. what about the second question i posted in th
OpenStudy (anonymous):
?
OpenStudy (anonymous):
given this equation solve for b and give answer in exponential form? look at same question above. can u help me @satellite73?
OpenStudy (anonymous):
(13,5) lies on the graph of \(2\log_b( x)\). the value of b is
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OpenStudy (anonymous):
no the other question
OpenStudy (anonymous):
we know
\[2\log_b(13)=5\] and therefore
\[\log_b(13)=7.5\] thus
\[b^{7.5}=13\]
OpenStudy (anonymous):
this one
\[\log_{3b} t=M\]
OpenStudy (mertsj):
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