Can someone help me?
What do you need help with?
Use a calculator to find the given value. Round to four decimal places. sin 20 degree. 0.3584 2.7904 0.9336 0.3839
21 degree*
Do you not have a calculator? If you don't you can enter the problem into the box at http://www.wolframalpha.com/
thanks :)
can you help me with something else?
sure
Find the value of a in the diagram of the right triangle. Round to the nearest tenth. 21.6 in. 24.2 in. 5.0 in. 12.3 in
In this case, you know the opposite is 11 in, the hypotenuse is a, and the angle is 27 degrees We also know that \[\sin A = \left( opposite \over hypotenuse \right)\]so\[\sin (27)=\left( 11 \over a \right)\]Rearrange to solve for a
so what would the answer be?
\[a=\left( 11 \over \sin( 27) \right)\]You can use the same website I gave you above to calculate your answer.
how would I write that into alpha?
11/sin27
what answer did you get?
249.7?
when I put 11/sin27 into the box on the website I gave you, the answer was 22.2295819....
so outta these 21.6 in. 24.2 in. 5.0 in. 12.3 in which one would it be?
never mind I got it :)
I need more help , hold on.
A ladder leans against a building forming an angle of 55 degree. with the ground as shown in the diagram. The base of the ladder is 5 feet from the building. What is the length of the ladder? 9.1 feet 6.1 feet 7.1 feet 8.7 feet
I'll look at this new one but I just wanted to point out that I copied the answer incorrectly, I had gotten 24.2295819......typo.
it's okay :)
Okay, this new problem is exactly the same situation except in this case we are dealing with the adjacent over the hypotenuse, which is related by the cosine so\[\cos A =\left( adjacent \over hypotenuse \right)\]The adjacent is 5 ft and use x for the hypotenuse and 55 degrees for the angle, our equation becomes \[\cos(55)=\left( 5 \over x \right)\]
Okay, how would I type this on alpa?
if you rearrange again as I did above\[x=\left( 5 \over \cos 55 \right)=5/\cos55\]
Okay thank you :) A large totem pole near Kalama, Washington, is 106 feet tall. At a particular time of day, the angle of elevation to the top of the pole from the end of the shadow it casts is 23 degree. What is the length of the shadow? Round to the nearest tenth. 115.2 ft 45.0 ft 271.3 ft 249.7 ft
WRONG Attachment , heres the one.
Ok this is not what OS is for As per the code of conduct you are to \(guide\) askers to the solution only @Missyxo we've talked about this @pfenn1 please make her answer the question herself, do not directly provide the answers
@TuringTest I already have help.
I ma here to make sure that help is up to the standards of this site :)
ok.
so far it has not been, though pfenn seems to be trying, which is cool but we need \(you\) to answer the questions based on hints given by our tutors
Okay @TurningTest. This is yet another very similar problem but this time we are given the opposite (106) and are asked for the adjacent. |dw:1336099718355:dw| The drawing is in case you aren't familiar with the definitions of adjacent et al.
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