How do I solve this integral? \[\int\limits_{-\infty}^{0} \frac{x^{2}}{9 + x^{6}}dx\] I have tried trig sub but it is really ugly. I assume by completing the square but the answer is pi/9
its an improper integral
note that I took this integral from \[\int\limits\limits\limits_{-\infty}^{\infty} (x^{2}/(9 + x^{2}))dx\]
oh crud I wrote it wrong
you have to set up the limit as x approaches infinity of that integral from t to 0 instead of infinity to 0
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yeah I know this question is in regards to finding the integral of this function
you can long-divide, then use partial fractions
oh that's a six in the bottom?!?
did I rewrite it correctly?
Let u=x^3.
^yep
It will become arctan(something).
you could make it a product and use int by parts
that would be a huge mess
you could derive a quotient rule base integration formula in the same way you get the int by parts one :P
the integral is \[\int\limits_{-\infty}^{\infty} x^{2}dx/(9+x^{6})\]
trig sub also seems hopeless :\
Have you tried letting u=x^3 to get rid of the x^2 on top?
okay maybe we have to evaluate the riemann sum
yeah that seems like the best way to solve it :)
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