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Mathematics 10 Online
OpenStudy (anonymous):

x-4=log3 243

OpenStudy (kropot72):

\[x-4=\log_{3} 243\] \[3^{(x-4)}=243\] \[(x-4)\times \ln 3=\ln 243\] \[x-4=\ln 243/\ln 3\] Do you follow?

OpenStudy (anonymous):

no

OpenStudy (kropot72):

What step is troubling you?

OpenStudy (anonymous):

everything

OpenStudy (kropot72):

If (x-4) is the log to base 3 of 243 then 3 raised to the power of (x-4) must equal 243. This follows from the basic definition of a logarithm.

OpenStudy (kropot72):

To finish off \[x-4=(\ln 243)/\ln 3=5\] x - 4 = 5 x = 9

OpenStudy (maheshmeghwal9):

\[x-4=\log3 (243) \rightarrow x=\log 3(243)+4\log 3(3). \]

OpenStudy (maheshmeghwal9):

\[since \log 3(3)=1. \]

OpenStudy (maheshmeghwal9):

\[Now,We see\]

OpenStudy (maheshmeghwal9):

\[\log 3(243) +\log 3(3)^4 \]

OpenStudy (maheshmeghwal9):

\[\log 3(243)+\log 3(81)\]

OpenStudy (maheshmeghwal9):

\[\log 3(243*81)=\log 3(19683) \]

OpenStudy (maheshmeghwal9):

\[\log 3(3^6) \]

OpenStudy (maheshmeghwal9):

\[6\log 3(3)= \]

OpenStudy (maheshmeghwal9):

\[6.\]

OpenStudy (anonymous):

not good n math and im lost and u walk me through it

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