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x-4=log3 243
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\[x-4=\log_{3} 243\] \[3^{(x-4)}=243\] \[(x-4)\times \ln 3=\ln 243\] \[x-4=\ln 243/\ln 3\] Do you follow?
no
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If (x-4) is the log to base 3 of 243 then 3 raised to the power of (x-4) must equal 243. This follows from the basic definition of a logarithm.
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To finish off \[x-4=(\ln 243)/\ln 3=5\] x - 4 = 5 x = 9
\[x-4=\log3 (243) \rightarrow x=\log 3(243)+4\log 3(3). \]
\[since \log 3(3)=1. \]
\[Now,We see\]
\[\log 3(243) +\log 3(3)^4 \]
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\[\log 3(243)+\log 3(81)\]
\[\log 3(243*81)=\log 3(19683) \]
\[\log 3(3^6) \]
\[6\log 3(3)= \]
\[6.\]
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not good n math and im lost and u walk me through it
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