A die is rolled 20 times and the number of twos that come up are tallied. find the propabilty of getting exactly four twos
A. 0.202 B. 0.075 C. 0.101 D. 0.083
which one would it be?
that was wrong it would be \[\dbinom{20}{4}(\frac{1}{6})^4(\frac{5}{6})^{16}\]
reasoning that you got 4 two, each of which has probability \(\frac{1}{6}\) and therefore 14 not two each with probability \(\frac{5}{6}\) and \(\binom{20}{4}\) different was to get that
i keep thinking 14 but of course 20 - 4 = 16
but i needed it round it to a deciaml yaa now(:
.2022 it looks like
go with answer 1
yes(: haaaa thanks so muuch(: . wanna help me with another ?
on line class?
yeah sure
yeaaah lol
Two marbles are drawn without replacement from a box with 3 white, 2 green, 2 red, and 1 blue marble. Find the probability. The second marble is white given the first marble is blue.
A. B. C. D.
it has to be a fraction
oh this we just think one marble is gone, it was a blue one there are now 7 marbles in the bag, 3 are white \[\frac{3}{7}\]
hope that is an answer choice, and it was much easier to compute than the last one
thanks so much(: i hate all this math bullpellet its hardd .
yeah probability can be a pain but you have to admit the last one didn't require much right? 7 marbles left, 3 are white? not like the last one
haa yeaah way less harder(:
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